Parents that are heterozygous for having freckles (dominant) are . . . When they are crossed, the offspring will have a 75% chance of having the dominant allele and a 25% chance of having the recessive allele Conclude that option C is correct because it states that 75% of the offspring will have freckles
Punnett Squares | CK-12 Foundation In this cross, known as a dihybrid cross, both parents are heterozygous for pod color (Gg) and pod form (Ff) Test your understanding by answering the questions based on the given cross with the help of the Punnett square
Lab Report: Genetic Crosses 1 | Wyzant Ask An Expert Imagine a mother and a father who both have freckles and are heterozygous for the trait, or Ff They are the P generation, or parent generation Create a Punnett square to show their offspring, the F1 generation
in humans having freckles F is dominant to not having freckles f If both parents have the genotype FF (homozygous dominant), all of their offspring will also have the genotype FF This is because each parent can only pass on one of their F alleles to their offspring Here is a Punnett square that illustrates this: So, all of the offspring will have freckles
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